Djnz r0 loop
WebDec 15, 2024 · ODD: DJNZ R0, LOOP END 9. WAP to count odd number from a series of ten 8-bit numbers. ORG 00H MOV R0, #12H MOV R3, 0AH MOV R1, #00H LOOP: MOV A, @R0 RRC A JNC ODD ... DJNZ R7, LOOP END 14. WAP to find 2’s complement of 16-bit number. MOV R0,#02H MOV A,#0FH CPL A MOV B,A MOV A,R0 CPL A ADD A,#01H … WebMOV R0,#150 LOOP: MOV R1,#200 LOOP1: NOP NOP DJNZ R1,LOOP1 DJNZ R0,LOOP RET END Chương trình trên chip viết cho các chân VĐK port 2 nhé..các bạn copy về …
Djnz r0 loop
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WebApr 9, 2024 · 51单片机DJNZ指令循环次数问题 这是个死循环吧,R0永远不能减到0的。每次减1不为零就跳到loop那继续执行,然后R0又是3了,所以永远跳不出去吧!51单片机流水灯依次点亮循环两次怎么实现?只循环两次! #includereg52.h // 这是下图的程序,... Web答: mov r0,#31h mov r1,30h mov 40h,#00h loop: mov a,@r0 cjne a,40h,l1 sjmp again l1: jnc l2 sjmp again l2: mov 40h,a again: inc r0 djnz r1,loop sjmp $ 15、略 16、在以 2000h 为首地址的存储区内,存放 20 个用 ascii 码表示的 0~9 之间的数,试编 程,将
WebApr 19, 2024 · Whereas if Indirect addressing is used, a loop can be used, making the process more efficient. ... A //Loop statement to place values at memory locations 40H … WebApr 30, 2016 · DJNZ R0,loop ; next iteration: RET: END << Previous:: Up:: Next >> Related topics: 8051 Program - sorting ascending order 8051 Program - bubble sort ascending …
Web操作者可通过按钮和开关控制步进电机的旋转速度和方向,正反转速度均要求在1~7挡变化,0档为停车,1~7挡速度随数字增大逐渐加快,其速度挡位和旋转方向应能在数码管上显示出来。 WebA tag already exists with the provided branch name. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior.
WebORG 0000H ; start of the program at location 0000H MOV A , P0 ; Using port0 to give the input MOV R0 , # 08H ; Counter MOV R1 , # 00H ; Clear R1 initially LOOP : RLC A ; …
WebRepeating a sequence of instructions a certain number of times is called a loop. An instruction DJNZ reg, label is used to perform a Loop operation. In this instruction, a … crompton self priming pumpWebTo obtain a delay of 0.5 seconds, the 16-bit timer is initiated to 50,000 and the loop counter register R0 is initiated to 10. The first instruction in the interrupt service routine TIMER0, … buffoon\\u0027s 85Web计算机应用系统方面的编程题 解:mov a,r1 mov r0,a(2)外部ram 20h单元内容送r0。解:mov r0,#20h movx a,@r0 mov r0,a(3)外部ram 20h单元内容送内部r... buffoon\u0027s 86WebBài tập dài vi xử lý. Câu 10: Viết CT con đổi n ký tự thành chữ hoa (nếu đang là chữ thường). Biết chuỗi ký tự trong bộ nhớ có địa chỉ đầu trong R0 , độ dài trong R7. Bài làm: Giả thiết n nhỏ hơn 256, lưu tại R1. Bộ nhớ là RAM trong. BÀI TẬP DÀI VI XỬ LÝ Họ tên ... cromptons grange over sandsWebMOV R0,#30H ;block source address on 30h MOV R1,#50H ;Destination address 50h ;following routing takes 5 numbers ;starting from 30h location ;send to the 50h location AGAIN: MOV A,@R0 MOV @R1,A INC R0 INC R1 DJNZ R3,AGAIN SJMP $ ;termination of the program END RESULT: After execution: Or . Microcontrollers Lab Manual 06ESL47 … buffoon\\u0027s 88http://vlsi.hongik.ac.kr/lecture/com/ucom_ch3_24.pdf buffoon\u0027s 84WebStatement 2: – store the higher nibble of r7 in to both nibbles of r6. Solution: –first we shall get the upper nibble of r7 in r6. Then we swap nibbles of r7 and make OR operation with r6 so the upper and lower nibbles are duplicated. Statement 3: – … buffoon\\u0027s 89