Web13 okt. 2024 · Step-by-step explanation: The given AP is,27,24,21,.... Here first term= a=27 common difference=d=24-27=-3 Let the nth term of the AP=0 => a+ (n-1)d=0 =>27+ (n-1) (-3)=0 => (n-1)= (-27)/ (-3) => n-1=9 => n=9+1 => n=10 So, the 10th term of the AP is 0. hope it will help you. Advertisement dawin32arpit Answer: 10 please mark as brainlist answer Web8 feb. 2024 · answered Feb 8, 2024 by Beepin (59.2k points) selected Feb 9, 2024 by KumkumBharti Best answer In the given A.P; a = 24, d = 4, Sn = 72 we have Sn = n/2 {2a + (n – 1)d} 72 = n/2 {2 (24) + (n – 1) (-4)} = 144 = n {48 – 4n + 4} ⇒ 144 = n {52 – 4n} ⇒ 144 = 52n – 4n2 ⇒ 4n2 – 52n + 144 = 0 ⇒ n2 – 13n + 36 = 0 ⇒ (n – 9) (n – 4) = 0 ∴ n = 9, 4
How many terms of AP: 27, 24, 21, ……… should be taken
WebHow many terms of the AP 26,21,16,11,.... are needed to give the sum 11? Medium Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions The first and last terms of an AP are 1 and 11 respectively. If the sum of its terms is 36, find the number of terms. Medium View solution > Evaluate the given series 7+12+17+.....+102= ..... Web10 okt. 2024 · We have to find the number of terms that must be taken so that their sum is 180. Solution: Let the number of terms be n. First term ( a) = 45 Common difference ( d) = 39 − 45 = − 6 We know that, S n = n 2 [ 2 a + ( n − 1) d] ⇒ 180 = n 2 [ 2 × 45 + ( n − 1) × ( − 6)] ⇒ 180 = n 2 [ 90 − 6 n + 6] ⇒ 360 = n ( − 6 n + 96) ⇒ 6 × 60 = 6 ( − n 2 + 16 n) the pocahontas theatre
RD Sharma Solutions for Class 10 Maths Chapter 9 Arithmetic
WebEasy Solution Verified by Toppr First term, a=18; common difference, d=16−18=−2 n th terms sum is given by S n= 2n(20+(n−1)d)=0 ⇒2a+(n−1)d=0 ⇒36−2(n−1)=0 ⇒36=2n−2 ⇒2n=32 ⇒n=19. or, n=16. Was this answer helpful? 0 0 Similar questions How many terms of AP:27,24,21,..... should be taken so that their sum is zero? What is the value of that … Web25 jul. 2024 · let first term of the AP be a1= -10 second term of the AP be a2=-7 and common difference be d. d=a2-a1 d=-7- (-10) d=-7+10 d=3 so common difference is d=3 we know that, Sum of n terms in the AP is, Sn=n/2 [2a1+ (n-1)d] 104=n/2 [2×-10 + (n-1)3] 104×2=n [-20+3n-3] 208=n [3n-23] 208=3n^2-23n 3n^3-23n-208=0 3n^2-39n+16n-208=0 … Web29 mrt. 2024 · Given AP 24, 21, 18,………. Here, a = 24 d = 21 – 24 = –3 Also, given Sum = 78 Sn = 78 We have to find value of n Putting these values in equation Sum = 𝒏/𝟐 [𝟐𝒂+ (𝒏−𝟏)𝒅] … the pocket decorator