In an ap sum of first 10 terms is-150
WebThe sum of n terms of an AP can be found using one of the following formulas: S n = n/2 (2a+ (n−1)d) S n = n/2 (a 1 +a n) Here, a = a 1 = the first term, d = the common difference, n = number of terms, a n = n th term, S n … WebIn an A.P. the sum of first ten terms is -150 and the sum of its next 10 term is -550. Find the A.P. Answer: Solution: The sum of n terms of AP is the addition of first n terms of the …
In an ap sum of first 10 terms is-150
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WebThe sum of n terms of AP will be: Sum = a + (a+d) + (a+2d) …… + (l-2d) + (l-d) + l——————– (3) where l= a+ (n-1)d Writing in reverse order, the sum will still remain same. Sum =l+ (l-d)+ (l-2d)..…+ (a+2d)+ (a+d)+a——————- (4) Adding equations 3 and 4, we get 2 × Sum = (a+l)+ [ (a+d)+ (l-d)]………+ [ (l-d)+ (a+d)]+ (l+a)] WebJul 29, 2024 · In an AP, the sum of first ten terms is -150 and the sum of its next ten terms is -550. Find the A.P.I have provided the easiest solution of above question, ......
WebApr 2, 2024 · The median of the distribution given below is 14.4. Find the values of x and y, if the sum of frequency is 20. Find the common difference ' d ' of an AP whose first term is 10 and the sum of the first 14 terms is 1505 . For what value of ' n ', are the nth terms of the APs : 9,7,5,….. and 15,12,9,…. the same? WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty …
Webgiven S10 = a1+a2+...+10 = 150. But we know that: s10 = (a1+a10)*10/2 = 150. ==> a1+a10 = 150/5. ==> a1+a10 = 30. ==> a10 = 30 - a1...... (1) But a10 = a1 + 9*3 = a1 + 27. ==> a10 = … WebMar 19, 2024 · Given that sum of the first 10 terms of an A.P. is -150. S10 = -150 And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum of next 10 terms S20 = -150 + -550 = -700 Now, having S10 = 10 2 10 2 (2a + (10 − 1)d) -150 = 5 (2a + 9d) -30 = 2a + 9d 2a + 9d = -30 . . . . (1) And,
WebHere, we are given S 10 = -150 and sum of the next ten terms is −550. Let us take the first term of the A.P. as a and the common difference as d. So, let us first find a10. For the …
WebLesson 4: Sum of first n terms of an AP. Arithmetic series intro. Arithmetic series formula. Worked example: arithmetic series (sum expression) Finding first term and common … rcog caesarean section for maternal requestWebIn an Ap of 50 terms the sum of first 10 terms is 210 and sum of its 15 terms is 2565.find the ap Report ; Posted by Amena Haseen 5 years, 5 months ago. CBSE > Class 10 > Mathematics ... Xi 0-25 25-50 50-75 75-100 100-125 125-150 150- 175 xi 4 8 x 15 10 7 5 and median is 90 find x. Report ; Posted by Manas Dhiman 1 day, 18 hours ago. rcog careersWebMar 19, 2024 · Given that sum of the first 10 terms of an A.P. is -150. S10 = -150. And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum … rcog breech vaginal birthWebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms. Q. rcog careers dayrcog care of women with obesity in pregnancyWebConsider an arithmetic progression (AP) whose first term is a 1 (or) a and the common difference is d.. The sum of first n terms of an arithmetic progression when the n th term is NOT known is S n = (n/2) [2a + (n - 1) d]; The sum of first n terms of an arithmetic progression when the n th term(a n) is known is S n = n/2[a 1 + a n]; Example: Mr. Kevin … rcog buildingWebApr 8, 2024 · In an AP of 50 terms, the sum of the first 10 terms is 210 and the sum of its last 15 terms is 2565. Find the AP. Questions & Answers CBSE Mathematics Grade 10 Arithmetic Progression Answer In an AP of 50 terms, the sum of the first 10 terms is 210 and the sum of its last 15 terms is 2565. Find the AP. Last updated date: 04th Apr 2024 • sims bustin out ps2